![]() So that way we can take into account any unit. I have created a datediff function that does almost everything sql server does. I would like to expand on Riki_tiki_tavi's answer and get the data out there. datediff(yy, '', '') = 2 // 2 changes of year repeated int.frac timeunit, e.g.: 1 year 2 months 3.4 days 5 hours 6 minutes 7 seconds 8 milliseconds. datediff(mm, '', '') = 23 // 23 changes of month datediff(dd`, '', '') = 704 // 704 changes of day in this interval The following are my best attempt at replicating the logic correctly. There is less than 2 years between those dates, meaning only 1 whole year has passed, but 2 year boundaries have crossed, from 2010 to 2011, and from 2011 to 2012. That's why datediff(yy, '', '') is 2, and not 1. ![]() Not how many days, months, or years it is between them. That means how many day boundaries, month boundaries, or year boundaries, are crossed. This function returns the count (as a signed integer value) of the specified datepart boundaries crossed between the specified startdate and enddate. ![]() The asker wants to get the same result as for when running the MS SQL Server function DATEDIFF ( datepart, startdate, enddate ) where datepart takes dd, mm, or yy. I noticed that Postgres seems to convert Extract (month from currenttimestamp) to datepart ('month', currenttimestamp), you can also do Extract ('month' from currenttimestamp). First lets understand the question fully. One possible way is to add a datediff function to Postgres, but the problem is that month/day/year etc is a keyword not a string like 'month'. This question is full of misunderstandings. SELECT datediff('month', ''::date, NOW()::date) Sql Server Delete Rows From Sql Where Timestamp Second Is Postgresql. The PostgreSQL formatting functions provide a powerful set of tools for converting various data types (date/time, integer, floating point, numeric) to formatted strings and for converting from formatted strings to specific data types. * Get months count between specified and current date */ caillou summer vacation sql server current timestamp milliseconds mean Web28 nov. ![]() SELECT datediff('year', ''::date, ''::date) SELECT datediff('month', ''::date, ''::date) PostgreSQL POSITION() function PostgresQL ANY / SOME Operator ( IN vs ANY ) PostgreSQL Substring - Extracting a substring from a String How to add an auto-incrementing primary key to an existing table, in PostgreSQL PostgreSQL STRINGTOARRAY()function mysql FINDINSET equivalent to postgresql PL/pgSQL Variables ( Format Dates ) The Ultimate Guide to PostgreSQL Date By Examples Data Type. Usage: /* Get months count between two dates */ RETURN date_part('year', age) * 12 + date_part('month', age) RETURN date_part('year', date_to) - date_part('year', date_from) Get difference between two timestamp in postgresql by seconds with an example:ĭifference between two timestamp in seconds can be calculated using EPOCH function.Almost the same function as you needed (based on atiruz's answer, shortened version of UDF from here) CREATE OR REPLACE FUNCTION datediff(type VARCHAR, date_from DATE, date_to DATE) RETURNS INTEGER LANGUAGE plpgsql Select *,EXTRACT(EPOCH FROM (birthtime -fin_time ))/60 as diff_time_min from student_detail2 Get difference between two timestamp in postgresql by minutes with an example:ĭifference between two timestamp in minutes can be calculated using EPOCH function by dividing 60 because EPOCH returns difference in seconds as shown below Select *,EXTRACT(EPOCH FROM (birthtime -fin_time ))/3600 as diff_time_hours from student_detail2 Get difference between two timestamp in postgresql by hours with an example:ĭifference between two timestamp in hours can be calculated using EPOCH function by dividing 3600 because EPOCH returns difference in seconds as shown below
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